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More Project fucking Euler

Topics: project euler

2010-12-22


I am proceeding with my attempt at Project Euler Problem #254[1]. It revolves around reversing functions. *g(i)* is basically the reverse of *sf(n)*. What I am doing is taking an Integer (*i*) and returning every number *k* with the following property: If one adds up the digits in *k*, one comes up with *i*. Here is my code so far (see if you can spot the obvious error before I continue!):


listToInteger :: [Integer] -> Integer
listToInteger xs = listToInteger' $ reverse xs
    where listToInteger' [] = 0
          listToInteger' (x:xs) = x + 10 * listToInteger' xs

integersAddToInteger :: Int -> [Integer]
integersAddToInteger i = sort . map listToInteger . digitsAddTo . take i $ cycle [1]

digitsAddTo :: [Integer] -> [[Integer]]
digitsAddTo [] = []
digitsAddTo [x] = [[x]]
digitsAddTo xs = thirdSet xs ++ secondSet xs
    where secondSet xs    = digitsAddTo $ [first xs] ++ rest xs
          thirdSet (x:xs) = map (x:) . digitsAddTo $ xs
          first (a:b:xs)  = a + b
          rest (a:b:xs)   = xs

When I call, for example, `integersAddToInteger 5`, I get this:


[5,14,23,32,41,113,122,131,212,221,311,1112,1121,1211,2111,11111]

Now, the obvious error is that if I want to find all *k* for an *i* greater than 9, the function `digitsAddTo` will begin using double digit numbers. I shall now attempt to fix this problem.



1: http://projecteuler.net/index.php?section=problems&id=254



tzifur (Martenblog home)

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